Tuesday, December 6, 2011

Relativity?

A swimmer heads directly across a river of width 10m at a speed of 1.2m/s. If there is a constant cross-current along the shore of 0.8m/s, find the angle that his course makes with the far bank, and determine how far downstream he has been swept by the current when he arrives at the opposite bank.|||10m at 1.2m/s means he will arrive on shore in 10/1.2 or 8.33s. In this time he has drifted downstream .8m/s*8.33s or 6.67m. Using trig: the angle with the far bank = tan^-1(10/6.67) = 56.3 degrees

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